Property Tax & Income in Steuben County, Indiana
Steuben County has an effective property tax rate of 0.57%. On the median home value of $216,200, that's roughly $1,242 per year. Median household income is $74,911.
What you'll pay, at a glance
Property taxes are the largest local tax most homeowners pay. The effective rate measures the real tax bill as a share of home value — a more useful number than the nominal “mill rate,” because assessment practices vary county to county.
| Metric | Steuben County | Indiana (state context) |
|---|---|---|
| Effective property tax rate1 | 0.57% | 0.66% |
| Median home value1 | $216,200 | — |
| State income tax3 | top rate 2.95% | top rate 2.95% |
| State sales tax3 | 7.00% combined | 7.00% combined |
How this is calculated
The effective property tax rate is the median real-estate tax bill divided by the median home value — both for owner-occupied homes, from the U.S. Census Bureau's American Community Survey (ACS 5-year estimates)1. Median income is also from the ACS1. Federal and state income-tax figures use IRS2 and Tax Foundation3 data.
About Steuben County, IN
Steuben County's effective property tax rate of 0.574% sits below Indiana's statewide median of 0.657%, and it ranks 73rd out of 92 counties on this measure — meaning roughly four in five Indiana counties levy a higher rate. The gap with the national median of 0.794% is wider still. On a median home value of $216,200, that rate yields an annual real-estate tax bill of about $1,242. Households here earn a median of $74,911, with per-capita income at $39,731. The county's largest city, Angola, anchors a area that includes Fremont and Pleasant Lake. A rate this far down the state ranking signals that property taxes take a smaller bite of home value than in most of Indiana, though the actual dollar amount owed still depends on each property's assessed value and any local exemptions or credits that apply.