Property Tax & Income in Buchanan County, Iowa
Buchanan County has an effective property tax rate of 1.36%. On the median home value of $176,000, that's roughly $2,390 per year. Median household income is $78,236.
What you'll pay, at a glance
Property taxes are the largest local tax most homeowners pay. The effective rate measures the real tax bill as a share of home value — a more useful number than the nominal “mill rate,” because assessment practices vary county to county.
| Metric | Buchanan County | Iowa (state context) |
|---|---|---|
| Effective property tax rate1 | 1.36% | 1.32% |
| Median home value1 | $176,000 | — |
| State income tax3 | top rate 3.80% | top rate 3.80% |
| State sales tax3 | 6.94% combined | 6.94% combined |
How this is calculated
The effective property tax rate is the median real-estate tax bill divided by the median home value — both for owner-occupied homes, from the U.S. Census Bureau's American Community Survey (ACS 5-year estimates)1. Median income is also from the ACS1. Federal and state income-tax figures use IRS2 and Tax Foundation3 data.
About Buchanan County, IA
Property taxes in Buchanan County run at an effective rate of 1.358%, which sits slightly above Iowa's statewide median of 1.319%. That gap is narrow, but it places the county 38th among Iowa's 99 counties for property tax rate, landing it just past the middle of the pack. Against the national median of 0.794%, however, the difference is far more striking — Buchanan County's rate is roughly 1.7 times the U.S. figure. A median home here, valued at $176,000, carries an annual real-estate tax bill of about $2,390, set against a median household income of $78,236 and per-capita income of $36,527. Independence is the largest of the county's principal communities, alongside Aurora and Hazleton. What this signals is a county whose property tax load tracks closely with Iowa norms but stands well above what most American homeowners pay.